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Home >> Advice >> Help! Maths
16.12.2006, 05:52 quote
even when I have sobered up this thread is gonna maked NO sense at all!
Maths ............ feck off! isn't that why we have calculators!!!
16.12.2006, 17:05 quote
If a train takes 3 hours to get to London, how long does it 3 men to dig a hole with a piece of string.
16.12.2006, 17:11 quote
| Cidem wrote: |
| 42 |
Damn you to clever for me....try this one.
If a man in a space suit uses his oxygen at a rate of 5 cubic metres an hour, how long is it before my dinners ready.
16.12.2006, 17:29 quote
| Morillo wrote: | ||
Damn you to clever for me....try this one. If a man in a space suit uses his oxygen at a rate of 5 cubic metres an hour, how long is it before my dinners ready. |
Too late, your dinner was ready yesterday!
16.12.2006, 17:36 quote
| Cidem wrote: |
| 31 feet, 6 & 5/8 inches |
I'l catch you out in a minute....right answer this then clever clogs...
A silk worm produces 2 feet of silk an hour, therefore if you had 25 silk worms how much milk can you get out of a cow before it comes home.
16.12.2006, 17:37 quote
| Redsback wrote: | ||||
Too late, your dinner was ready yesterday! |
If your not going to take this seriously please refrain from guessing the answers.
16.12.2006, 17:38 quote
| Morillo wrote: | ||||||
If your not going to take this seriously please refrain from guessing the answers. |
I was going to any way. You and cidem are far too clever for me.
16.12.2006, 17:43 quote
Yes Red...dont get involved in things you dont understand, get back to the kitchen sink, there's a dear...
16.12.2006, 17:44 quote
| Morillo wrote: |
| Yes Red...dont get involved in things you dont understand, get back to the kitchen sink, there's a dear... |
Unchain me from the bed then!
16.12.2006, 17:52 quote
| Cidem wrote: | ||||
must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts..... Oh, Morillo.... that was a trick question: the milk would have become cheese in the silk therefore the answer is 3 blocks of mild cheddar  |
Ha got you at last...you fell right into my trap...the answer is edam as the cows were dutch...bad luck.
16.12.2006, 17:52 quote
| Cidem wrote: | ||||
must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts.....must not think naughty thoughts..... |
No you mustn't Cidem! Behave man, you're married .... or with partner.... or summink!
16.12.2006, 18:11 quote
| Cidem wrote: |
| damn you morillo ! oh well 2 out of 3 isn't bad I suppose
Red: I know.... but if you will put those thoughts into my head in the first place    |
right, on Pols instructions (see 'anything else') I am to flirt outrageously on her behalf, so.....
chained to the bed in a leather basque and stockings, I am here to do your bidding oh great one
16.12.2006, 19:57 quote
| Gizzemoto wrote: |
| Any one in here good at maths, i need lots of help
1. Show how the area under the Time/velocity curve is equal to the distance traveled. A car traveling in a straigh line, accelerates uniformly from rest with a uniform acceleration of 2 m/s2 to a maximum speed of 30 m/s. It drives at this speed for 12 seconds and then decelerates to rest in a further 10 seconds. Find the time spent accelerating, the total distance covered, the magnitude of the deceleration?? Any ideas, solutions |
Havent done anything like that for years..but I am trying to remember how to do it by "common sense"
1. The area "under" a graph is always the integral of it....
It is quite easy to understand if you imagine the following:
if you have a straight line with a disance of e.g. f(x)=5, then the area
of the rectangle between 0 and 10 would be 10*5,. so the integral of f(x)=5x. If the function is f(x)=x the integral is x^2...etc.
So if you have a function that tells you the velocity after a certain time (you need the acceleration for it), the area below the function is the integral of that function.
v = a * t (speed = acceleation * time).
Example: Acceleraion is 5m/s^2 this means after 1 second the speed is 5m/s and after 2 seconds the speend is 10 m/s etc....
v(t) = a*t. The integral would be 0.5 a*t^2 (oh no!..almost forgot how to integrate..quite shocking
)
The distance travelled is the speed * time.
If you want to compare it to the integral above, you need to get rid of the speed inside the equation.
Speed = a*t.
So distance travelled is v*t=a*t*t = a*t^2
So the area below is not the distance travelled, but half the distance travelled!
Q.E.D
2. just add the 3 different parts/areas under the graph together....to get the total distance travelled. The rest is done using the equations above..just play around with them until you have an equation that give you the result depending on the parameters you know.
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